What are the solutions to the equation a^2+a-20=0 ?

The solutions to the equation a^2+a-20=0 are a=4,a=-5

Find the zeros of a^2+a-20=0

The zeros of a^2+a-20=0 are a=4,a=-5

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a^{2} + a - 20 = 0

a = 4, a = - 5

Solution steps

a^{2} + a - 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

a_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 1 + 9}{2 \cdot 1}, a_{2} = \frac{- 1 - 9}{2 \cdot 1}

a = \frac{- 1 + 9}{2 \cdot 1} : 4

a = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = 4, a = - 5

- x^{2} + 11 x - 24 = 0

- \frac{550 x ^{2}}{2} + \frac{2000 ( x - 4 ) ^{2}}{2} + 3200 = 0

- 7 a^{5} n^{2} = 2

x (x - 15) = 100

x, x^{2} + 4 x y + 4 y^{2} - 3 x + 4 y - 10 = 0

What are the solutions to the equation a^2+a-20=0 ?
The solutions to the equation a^2+a-20=0 are a=4,a=-5
Find the zeros of a^2+a-20=0
The zeros of a^2+a-20=0 are a=4,a=-5