What are the solutions to the equation factor 2x^2-7x=0 ?

The solutions to the equation factor 2x^2-7x=0 are x=0,x= 7/2

Find the zeros of factor 2x^2-7x=0

The zeros of factor 2x^2-7x=0 are x=0,x= 7/2

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2 x^{2} - 7 x = 0

x = 0, x = \frac{7}{2}

Decimal Notation

x = 0, x = 3.5

Solution steps

2 x^{2} - 7 x = 0

Factor

2 x^{2} - 7 x : x (2 x - 7)

x (2 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 7 = 0

Solve

2 x - 7 = 0 : x = \frac{7}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{7}{2}

x^{2} - 12 x + 13 = 0

- 0.5 x^{2} + 40 x - 300 = 15000

2 x^{2} + b x + c = 0

x^{2} - 2 x - 4 = 0

6 (3 x - 1) (2 x - 1) - 12 x^{2} = 7 x (2 x - 1)

What are the solutions to the equation factor 2x^2-7x=0 ?
The solutions to the equation factor 2x^2-7x=0 are x=0,x= 7/2
Find the zeros of factor 2x^2-7x=0
The zeros of factor 2x^2-7x=0 are x=0,x= 7/2