What are the solutions to the equation 5j^2=180 ?

The solutions to the equation 5j^2=180 are j=6,j=-6

Find the zeros of 5j^2=180

The zeros of 5j^2=180 are j=6,j=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 j^{2} = 180

j = 6, j = - 6

Solution steps

5 j^{2} = 180

Divide both sides by

5

j^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

j = 36, j = - 36

36 = 6

- 36 = - 6

j = 6, j = - 6

y, r^{2} = x^{2} + y^{2}

x^{2} - 5 x + 7 = 2 x + 1

7 m^{2} - 224 = 28 m

z^{2} - 6 z = 27

4 x^{2} + x + 9 = 0

What are the solutions to the equation 5j^2=180 ?
The solutions to the equation 5j^2=180 are j=6,j=-6
Find the zeros of 5j^2=180
The zeros of 5j^2=180 are j=6,j=-6