What are the solutions to the equation 7m^2-224=28m ?

The solutions to the equation 7m^2-224=28m are m=8,m=-4

Find the zeros of 7m^2-224=28m

The zeros of 7m^2-224=28m are m=8,m=-4

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7 m^{2} - 224 = 28 m

m = 8, m = - 4

Solution steps

7 m^{2} - 224 = 28 m

Move

28 m

to the left side

7 m^{2} - 224 - 28 m = 0

Write in the standard form

a x^{2} + b x + c = 0

7 m^{2} - 28 m - 224 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 7 ( - 224 )}{2 \cdot 7}

(- 28)^{2} - 4 \cdot 7 (- 224) = 84

m_{1, 2} = \frac{- ( - 28 ) \pm 84}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- ( - 28 ) + 84}{2 \cdot 7}, m_{2} = \frac{- ( - 28 ) - 84}{2 \cdot 7}

m = \frac{- ( - 28 ) + 84}{2 \cdot 7} : 8

m = \frac{- ( - 28 ) - 84}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

m = 8, m = - 4

z^{2} - 6 z = 27

4 x^{2} + x + 9 = 0

t, 37 = 100 t - 16 t^{2}

t^{2} - 6 t + 5 = 0

16 (x + 5)^{2} = 1

What are the solutions to the equation 7m^2-224=28m ?
The solutions to the equation 7m^2-224=28m are m=8,m=-4
Find the zeros of 7m^2-224=28m
The zeros of 7m^2-224=28m are m=8,m=-4