What are the solutions to the equation 16(x+5)^2=1 ?

The solutions to the equation 16(x+5)^2=1 are x=-19/4 ,x=-21/4

Find the zeros of 16(x+5)^2=1

The zeros of 16(x+5)^2=1 are x=-19/4 ,x=-21/4

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16 (x + 5)^{2} = 1

x = - \frac{19}{4}, x = - \frac{21}{4}

Decimal Notation

x = - 4.75, x = - 5.25

Solution steps

16 (x + 5)^{2} = 1

Divide both sides by

16

(x + 5)^{2} = \frac{1}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = \frac{1}{16} : x = - \frac{19}{4}

Solve

x + 5 = - \frac{1}{16} : x = - \frac{21}{4}

The solutions to the quadratic equation are:

x = - \frac{19}{4}, x = - \frac{21}{4}

n^{2} + n - 6 = 0

0 = 2 x^{2} - 11 x + 5

x (x + 2) = 168

x^{2} + 16 = 10 x

2 x^{2} + 9 = 49

What are the solutions to the equation 16(x+5)^2=1 ?
The solutions to the equation 16(x+5)^2=1 are x=-19/4 ,x=-21/4
Find the zeros of 16(x+5)^2=1
The zeros of 16(x+5)^2=1 are x=-19/4 ,x=-21/4