What are the solutions to the equation x(x+2)=168 ?

The solutions to the equation x(x+2)=168 are x=12,x=-14

Find the zeros of x(x+2)=168

The zeros of x(x+2)=168 are x=12,x=-14

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x (x + 2) = 168

x = 12, x = - 14

Solution steps

x (x + 2) = 168

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 168

Move

168

to the left side

x^{2} + 2 x - 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 168 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 168) = 26

x_{1, 2} = \frac{- 2 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 26}{2 \cdot 1}, x_{2} = \frac{- 2 - 26}{2 \cdot 1}

x = \frac{- 2 + 26}{2 \cdot 1} : 12

x = \frac{- 2 - 26}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 12, x = - 14

x^{2} + 16 = 10 x

2 x^{2} + 9 = 49

- 3 x^{2} - x + 3 = 0

x^{2} + 16 x + 13 = 0

3 x^{2} - x - 173 = 11 x + 7

What are the solutions to the equation x(x+2)=168 ?
The solutions to the equation x(x+2)=168 are x=12,x=-14
Find the zeros of x(x+2)=168
The zeros of x(x+2)=168 are x=12,x=-14