What are the solutions to the equation -2u^2+4=1 ?

The solutions to the equation -2u^2+4=1 are u=sqrt(3/2),u=-sqrt(3/2)

Find the zeros of -2u^2+4=1

The zeros of -2u^2+4=1 are u=sqrt(3/2),u=-sqrt(3/2)

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- 2 u^{2} + 4 = 1

u = \frac{3}{2}, u = - \frac{3}{2}

Decimal Notation

u = 1.22474 \dots, u = - 1.22474 \dots

Solution steps

- 2 u^{2} + 4 = 1

Move

4

to the right side

- 2 u^{2} = - 3

Divide both sides by

- 2

u^{2} = \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{3}{2}, u = - \frac{3}{2}

7 x^{2} - 25 = 0

x^{2} - 10 x - 25 = 9

32 t - 16 t^{2} = 16

x, f = (x + 3) (x - k)

x^{2} - 3 x + 11 = 0

What are the solutions to the equation -2u^2+4=1 ?
The solutions to the equation -2u^2+4=1 are u=sqrt(3/2),u=-sqrt(3/2)
Find the zeros of -2u^2+4=1
The zeros of -2u^2+4=1 are u=sqrt(3/2),u=-sqrt(3/2)