What are the solutions to the equation 32t-16t^2=16 ?

The solutions to the equation 32t-16t^2=16 are t=1

Find the zeros of 32t-16t^2=16

The zeros of 32t-16t^2=16 are t=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

32 t - 16 t^{2} = 16

t = 1

Solution steps

32 t - 16 t^{2} = 16

Move

16

to the left side

32 t - 16 t^{2} - 16 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 32 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) ( - 16 )}{2 ( - 16 )}

3 2^{2} - 4 (- 16) (- 16) = 0

t_{1, 2} = \frac{- 32 \pm 0}{2 ( - 16 )}

t = \frac{- 32}{2 ( - 16 )}

\frac{- 32}{2 ( - 16 )} = 1

t = 1

The solution to the quadratic equation is:

t = 1

x, f = (x + 3) (x - k)

x^{2} - 3 x + 11 = 0

t = 3.3 t^{2} - 6 t + 12

x^{2} = 2 x + 2

2 x^{2} - 8 x + 15 = 0

What are the solutions to the equation 32t-16t^2=16 ?
The solutions to the equation 32t-16t^2=16 are t=1
Find the zeros of 32t-16t^2=16
The zeros of 32t-16t^2=16 are t=1