What are the solutions to the equation 2x^2-8x+15=0 ?

The solutions to the equation 2x^2-8x+15=0 are x=2+isqrt(7/2),x=2-isqrt(7/2)

Find the zeros of 2x^2-8x+15=0

The zeros of 2x^2-8x+15=0 are x=2+isqrt(7/2),x=2-isqrt(7/2)

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2 x^{2} - 8 x + 15 = 0

x = 2 + i \frac{7}{2}, x = 2 - i \frac{7}{2}

Solution steps

2 x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

Simplify

(- 8)^{2} - 4 \cdot 2 \cdot 15 : 214 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 14 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 14 i}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 14 i}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 14 i}{2 \cdot 2} : 2 + i \frac{7}{2}

x = \frac{- ( - 8 ) - 2 14 i}{2 \cdot 2} : 2 - i \frac{7}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{7}{2}, x = 2 - i \frac{7}{2}

4 x^{2} - 30 = 70

4 x^{2} - 4 x + 1 = 0

5 n^{2} - 10 n + 5 = 0

t, 8 l e f t (x - 2) l e f t (x + \frac{2}{5})^{2} = 0

- 6 x^{2} - 24 x = 0

What are the solutions to the equation 2x^2-8x+15=0 ?
The solutions to the equation 2x^2-8x+15=0 are x=2+isqrt(7/2),x=2-isqrt(7/2)
Find the zeros of 2x^2-8x+15=0
The zeros of 2x^2-8x+15=0 are x=2+isqrt(7/2),x=2-isqrt(7/2)