What are the solutions to the equation completesquare 4x^2-4x+1=0 ?

The solutions to the equation completesquare 4x^2-4x+1=0 are x= 1/2

Find the zeros of completesquare 4x^2-4x+1=0

The zeros of completesquare 4x^2-4x+1=0 are x= 1/2

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4 x^{2} - 4 x + 1 = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

4 x^{2} - 4 x + 1 = 0

Move

1

to the right side

4 x^{2} - 4 x = - 1

Divide both sides by

4

\frac{4 x ^{2} - 4 x}{4} = \frac{- 1}{4}

x^{2} - x = - \frac{1}{4}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{2})^{2} = 0

Solve

x - \frac{1}{2} = 0 : x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

5 n^{2} - 10 n + 5 = 0

t, 8 l e f t (x - 2) l e f t (x + \frac{2}{5})^{2} = 0

- 6 x^{2} - 24 x = 0

(52)^{2} = x^{2} + x^{2}

v^{2} - 6 v + 8 = 0

What are the solutions to the equation completesquare 4x^2-4x+1=0 ?
The solutions to the equation completesquare 4x^2-4x+1=0 are x= 1/2
Find the zeros of completesquare 4x^2-4x+1=0
The zeros of completesquare 4x^2-4x+1=0 are x= 1/2