What are the solutions to the equation x^2+12+11x+5+13x-17=180 ?

The solutions to the equation x^2+12+11x+5+13x-17=180 are x=6,x=-30

Find the zeros of x^2+12+11x+5+13x-17=180

The zeros of x^2+12+11x+5+13x-17=180 are x=6,x=-30

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x^{2} + 12 + 11 x + 5 + 13 x - 17 = 180

x = 6, x = - 30

Solution steps

x^{2} + 12 + 11 x + 5 + 13 x - 17 = 180

Refine

x^{2} + 24 x = 180

Move

180

to the left side

x^{2} + 24 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot ( - 180 )}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot (- 180) = 36

x_{1, 2} = \frac{- 24 \pm 36}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 36}{2 \cdot 1}, x_{2} = \frac{- 24 - 36}{2 \cdot 1}

x = \frac{- 24 + 36}{2 \cdot 1} : 6

x = \frac{- 24 - 36}{2 \cdot 1} : - 30

The solutions to the quadratic equation are:

x = 6, x = - 30

x^{2} - 8 x + 30 = 0

4 x^{2} + 1 = 325

20 z^{2} + 13 z + 2 = 0

(x + 10)^{2} = 144

7 x^{2} - x - 2 = 0

What are the solutions to the equation x^2+12+11x+5+13x-17=180 ?
The solutions to the equation x^2+12+11x+5+13x-17=180 are x=6,x=-30
Find the zeros of x^2+12+11x+5+13x-17=180
The zeros of x^2+12+11x+5+13x-17=180 are x=6,x=-30