What are the solutions to the equation 4x^2+1=325 ?

The solutions to the equation 4x^2+1=325 are x=9,x=-9

Find the zeros of 4x^2+1=325

The zeros of 4x^2+1=325 are x=9,x=-9

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4 x^{2} + 1 = 325

x = 9, x = - 9

Solution steps

4 x^{2} + 1 = 325

Move

1

to the right side

4 x^{2} = 324

Divide both sides by

4

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

20 z^{2} + 13 z + 2 = 0

(x + 10)^{2} = 144

7 x^{2} - x - 2 = 0

3 x^{2} + 13 = 256

y, x = y^{2} + 2 y + 3

What are the solutions to the equation 4x^2+1=325 ?
The solutions to the equation 4x^2+1=325 are x=9,x=-9
Find the zeros of 4x^2+1=325
The zeros of 4x^2+1=325 are x=9,x=-9