What are the solutions to the equation 3x^2+13=256 ?

The solutions to the equation 3x^2+13=256 are x=9,x=-9

Find the zeros of 3x^2+13=256

The zeros of 3x^2+13=256 are x=9,x=-9

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3 x^{2} + 13 = 256

x = 9, x = - 9

Solution steps

3 x^{2} + 13 = 256

Move

13

to the right side

3 x^{2} = 243

Divide both sides by

3

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

y, x = y^{2} + 2 y + 3

10 (r^{2} - 4) = 18

x, x^{2} + Y^{2} - 12 x + 10 Y + 61 = 0

x^{2} - 150 = 0

24 x^{2} + 152 x + 224 = 0

What are the solutions to the equation 3x^2+13=256 ?
The solutions to the equation 3x^2+13=256 are x=9,x=-9
Find the zeros of 3x^2+13=256
The zeros of 3x^2+13=256 are x=9,x=-9