What are the solutions to the equation 10(r^2-4)=18 ?

The solutions to the equation 10(r^2-4)=18 are r=sqrt(29/5),r=-sqrt(29/5)

Find the zeros of 10(r^2-4)=18

The zeros of 10(r^2-4)=18 are r=sqrt(29/5),r=-sqrt(29/5)

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10 (r^{2} - 4) = 18

r = \frac{29}{5}, r = - \frac{29}{5}

Decimal Notation

r = 2.40831 \dots, r = - 2.40831 \dots

Solution steps

10 (r^{2} - 4) = 18

Divide both sides by

10

r^{2} - 4 = \frac{9}{5}

Move

4

to the right side

r^{2} = \frac{29}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{29}{5}, r = - \frac{29}{5}

x, x^{2} + Y^{2} - 12 x + 10 Y + 61 = 0

x^{2} - 150 = 0

24 x^{2} + 152 x + 224 = 0

x^{2} + 15 x - 225 = 0

a^{2} - 5 a + 4 = 0

What are the solutions to the equation 10(r^2-4)=18 ?
The solutions to the equation 10(r^2-4)=18 are r=sqrt(29/5),r=-sqrt(29/5)
Find the zeros of 10(r^2-4)=18
The zeros of 10(r^2-4)=18 are r=sqrt(29/5),r=-sqrt(29/5)