What are the solutions to the equation a^2-5a+4=0 ?

The solutions to the equation a^2-5a+4=0 are a=4,a=1

Find the zeros of a^2-5a+4=0

The zeros of a^2-5a+4=0 are a=4,a=1

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a^{2} - 5 a + 4 = 0

a = 4, a = 1

Solution steps

a^{2} - 5 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

a_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

a = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

a = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 4, a = 1

4 X^{2} - 46 = X^{2} + 62

x^{2} + 4 x - 23 = 0

3 x^{2} - 19 x - 40 = 0

\frac{9 x ^{2} - 0}{9} - \frac{4 x - 0}{4} + 6 = 0

30.7 \cdot x^{2} + 57 = A x (x + 33.3) + B \cdot (x + 33.3) + C \cdot x^{2}

What are the solutions to the equation a^2-5a+4=0 ?
The solutions to the equation a^2-5a+4=0 are a=4,a=1
Find the zeros of a^2-5a+4=0
The zeros of a^2-5a+4=0 are a=4,a=1