What are the solutions to the equation x^2-sqrt(3)x+1=10 ?

The solutions to the equation x^2-sqrt(3)x+1=10 are x=(sqrt(3)+sqrt(39))/2 ,x=(sqrt(3)-sqrt(39))/2

Find the zeros of x^2-sqrt(3)x+1=10

The zeros of x^2-sqrt(3)x+1=10 are x=(sqrt(3)+sqrt(39))/2 ,x=(sqrt(3)-sqrt(39))/2

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x^{2} - 3 x + 1 = 10

x = \frac{3 + 39}{2}, x = \frac{3 - 39}{2}

Decimal Notation

x = 3.98852 \dots, x = - 2.25647 \dots

Solution steps

x^{2} - 3 x + 1 = 10

Move

10

to the left side

x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 9) = 39

x_{1, 2} = \frac{- ( - 3 ) \pm 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 39}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 39}{2 \cdot 1}

x = \frac{- ( - 3 ) + 39}{2 \cdot 1} : \frac{3 + 39}{2}

x = \frac{- ( - 3 ) - 39}{2 \cdot 1} : \frac{3 - 39}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 39}{2}, x = \frac{3 - 39}{2}

x (x - 12) = - 36

x^{2} - 11 x = 30

20 = - 5 x^{2} - 52 x

4 y^{2} + 9 = 0

v^{2} = - 28

What are the solutions to the equation x^2-sqrt(3)x+1=10 ?
The solutions to the equation x^2-sqrt(3)x+1=10 are x=(sqrt(3)+sqrt(39))/2 ,x=(sqrt(3)-sqrt(39))/2
Find the zeros of x^2-sqrt(3)x+1=10
The zeros of x^2-sqrt(3)x+1=10 are x=(sqrt(3)+sqrt(39))/2 ,x=(sqrt(3)-sqrt(39))/2