What are the solutions to the equation 4x^2+4x+15=0 ?

The solutions to the equation 4x^2+4x+15=0 are x=-1/2+isqrt(7/2),x=-1/2-isqrt(7/2)

Find the zeros of 4x^2+4x+15=0

The zeros of 4x^2+4x+15=0 are x=-1/2+isqrt(7/2),x=-1/2-isqrt(7/2)

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4 x^{2} + 4 x + 15 = 0

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

4 x^{2} + 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 15 : 414 i

x_{1, 2} = \frac{- 4 \pm 4 14 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 14 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 14 i}{2 \cdot 4}

x = \frac{- 4 + 4 14 i}{2 \cdot 4} : - \frac{1}{2} + i \frac{7}{2}

x = \frac{- 4 - 4 14 i}{2 \cdot 4} : - \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

4 x^{2} - 100 x = 0

x, 2 y + x^{2} = y^{3} + x

x, x^{2} - m x + 27 = 0

\frac{1}{4} x^{2} + \frac{4}{3} x - 7 = 0

n^{2} - 16 n + 67 = 4

What are the solutions to the equation 4x^2+4x+15=0 ?
The solutions to the equation 4x^2+4x+15=0 are x=-1/2+isqrt(7/2),x=-1/2-isqrt(7/2)
Find the zeros of 4x^2+4x+15=0
The zeros of 4x^2+4x+15=0 are x=-1/2+isqrt(7/2),x=-1/2-isqrt(7/2)