What are the solutions to the equation t^2+t=0 ?

The solutions to the equation t^2+t=0 are t=0,t=-1

Find the zeros of t^2+t=0

The zeros of t^2+t=0 are t=0,t=-1

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t^{2} + t = 0

t = 0, t = - 1

Solution steps

t^{2} + t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

t_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 1 + 1}{2 \cdot 1}, t_{2} = \frac{- 1 - 1}{2 \cdot 1}

t = \frac{- 1 + 1}{2 \cdot 1} : 0

t = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

t = 0, t = - 1

x^{2} - 8 x = - 20

x^{2} + x + 9 = 0

16 - x^{2} = - 20

3 x^{2} + 2 = 4 x

r, s = 2 π r h + 2 π r^{2}

What are the solutions to the equation t^2+t=0 ?
The solutions to the equation t^2+t=0 are t=0,t=-1
Find the zeros of t^2+t=0
The zeros of t^2+t=0 are t=0,t=-1