What are the solutions to the equation 2x^2+4n-16=0 ?

The solutions to the equation 2x^2+4n-16=0 are x=sqrt(2)sqrt(-n+4),x=-sqrt(2)sqrt(-n+4)

Find the zeros of 2x^2+4n-16=0

The zeros of 2x^2+4n-16=0 are x=sqrt(2)sqrt(-n+4),x=-sqrt(2)sqrt(-n+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 4 n - 16 = 0

x = 2 - n + 4, x = - 2 - n + 4

Solution steps

2 x^{2} + 4 n - 16 = 0

Move

4 n

to the right side

2 x^{2} - 16 = - 4 n

Move

16

to the right side

2 x^{2} = - 4 n + 16

Divide both sides by

2

x^{2} = 2 (- n + 4)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2 (- n + 4), x = - 2 (- n + 4)

Simplify

2 (- n + 4) : 2 - n + 4

Simplify

- 2 (- n + 4) : - 2 - n + 4

x = 2 - n + 4, x = - 2 - n + 4

x, 36 x^{2} + 36 y^{2} + 48 x - 108 y + 97 = 0

x^{2} - 2 a x + a^{2} = 0

18 x^{2} = 121

q + q^{2} - 56 = 0

(y - 2)^{2} = 2 y + 5

What are the solutions to the equation 2x^2+4n-16=0 ?
The solutions to the equation 2x^2+4n-16=0 are x=sqrt(2)sqrt(-n+4),x=-sqrt(2)sqrt(-n+4)
Find the zeros of 2x^2+4n-16=0
The zeros of 2x^2+4n-16=0 are x=sqrt(2)sqrt(-n+4),x=-sqrt(2)sqrt(-n+4)