What are the solutions to the equation x^2-2ax+a^2=0 ?

The solutions to the equation x^2-2ax+a^2=0 are x=a

Find the zeros of x^2-2ax+a^2=0

The zeros of x^2-2ax+a^2=0 are x=a

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x^{2} - 2 a x + a^{2} = 0

x = a

Solution steps

x^{2} - 2 a x + a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot a ^{2}}{2 \cdot 1}

(- 2 a)^{2} - 4 \cdot 1 \cdot a^{2} = 0

x_{1, 2} = \frac{- ( - 2 a ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 a )}{2 \cdot 1}

Simplify

\frac{- ( - 2 a )}{2 \cdot 1} : a

x = a

The solution to the quadratic equation is:

x = a

18 x^{2} = 121

q + q^{2} - 56 = 0

(y - 2)^{2} = 2 y + 5

14 - 5 (x + 7)^{2} = 0

x, 3 x^{2} - 18 x + 24 = 0

What are the solutions to the equation x^2-2ax+a^2=0 ?
The solutions to the equation x^2-2ax+a^2=0 are x=a
Find the zeros of x^2-2ax+a^2=0
The zeros of x^2-2ax+a^2=0 are x=a