What are the solutions to the equation 14-5(x+7)^2=0 ?

The solutions to the equation 14-5(x+7)^2=0 are x=sqrt(14/5)-7,x=-sqrt(14/5)-7

Find the zeros of 14-5(x+7)^2=0

The zeros of 14-5(x+7)^2=0 are x=sqrt(14/5)-7,x=-sqrt(14/5)-7

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14 - 5 (x + 7)^{2} = 0

x = \frac{14}{5} - 7, x = - \frac{14}{5} - 7

Decimal Notation

x = - 5.32667 \dots, x = - 8.67332 \dots

Solution steps

14 - 5 (x + 7)^{2} = 0

Move

14

to the right side

- 5 (x + 7)^{2} = - 14

Divide both sides by

- 5

(x + 7)^{2} = \frac{14}{5}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = \frac{14}{5} : x = \frac{14}{5} - 7

Solve

x + 7 = - \frac{14}{5} : x = - \frac{14}{5} - 7

The solutions to the quadratic equation are:

x = \frac{14}{5} - 7, x = - \frac{14}{5} - 7

x, 3 x^{2} - 18 x + 24 = 0

(u - 6)^{2} = 64

(2 - x) (- 2 - x) + 3 = 0

x, 25 x^{2} + 9 y^{2} - 18 y + 216 = 0

x^{2} - a x - 90 a^{2} = 0

What are the solutions to the equation 14-5(x+7)^2=0 ?
The solutions to the equation 14-5(x+7)^2=0 are x=sqrt(14/5)-7,x=-sqrt(14/5)-7
Find the zeros of 14-5(x+7)^2=0
The zeros of 14-5(x+7)^2=0 are x=sqrt(14/5)-7,x=-sqrt(14/5)-7