What are the solutions to the equation solvefor x,3x^2-18x+24=0 ?

The solutions to the equation solvefor x,3x^2-18x+24=0 are x=4,x=2

Find the zeros of solvefor x,3x^2-18x+24=0

The zeros of solvefor x,3x^2-18x+24=0 are x=4,x=2

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x, 3 x^{2} - 18 x + 24 = 0

x = 4, x = 2

Solution steps

3 x^{2} - 18 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 24 = 6

x_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 3}

x = \frac{- ( - 18 ) + 6}{2 \cdot 3} : 4

x = \frac{- ( - 18 ) - 6}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

(u - 6)^{2} = 64

(2 - x) (- 2 - x) + 3 = 0

x, 25 x^{2} + 9 y^{2} - 18 y + 216 = 0

x^{2} - a x - 90 a^{2} = 0

5 x^{2} - 10 x + 24 = 0

What are the solutions to the equation solvefor x,3x^2-18x+24=0 ?
The solutions to the equation solvefor x,3x^2-18x+24=0 are x=4,x=2
Find the zeros of solvefor x,3x^2-18x+24=0
The zeros of solvefor x,3x^2-18x+24=0 are x=4,x=2