What are the solutions to the equation 5x^2-10x+24=0 ?

The solutions to the equation 5x^2-10x+24=0 are x=1+isqrt(19/5),x=1-isqrt(19/5)

Find the zeros of 5x^2-10x+24=0

The zeros of 5x^2-10x+24=0 are x=1+isqrt(19/5),x=1-isqrt(19/5)

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5 x^{2} - 10 x + 24 = 0

x = 1 + i \frac{19}{5}, x = 1 - i \frac{19}{5}

Solution steps

5 x^{2} - 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 24}{2 \cdot 5}

Simplify

(- 10)^{2} - 4 \cdot 5 \cdot 24 : 295 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 95 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 95 i}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 2 95 i}{2 \cdot 5}

x = \frac{- ( - 10 ) + 2 95 i}{2 \cdot 5} : 1 + i \frac{19}{5}

x = \frac{- ( - 10 ) - 2 95 i}{2 \cdot 5} : 1 - i \frac{19}{5}

The solutions to the quadratic equation are:

x = 1 + i \frac{19}{5}, x = 1 - i \frac{19}{5}

- 2 p^{2} - 42 p = 32

- 6 - x + x^{2} = 0

a^{2} + 8^{2} = 9^{2}

- 12 x^{2} + 96 x + 100 = 0

b (x) = - 5 x^{2}

What are the solutions to the equation 5x^2-10x+24=0 ?
The solutions to the equation 5x^2-10x+24=0 are x=1+isqrt(19/5),x=1-isqrt(19/5)
Find the zeros of 5x^2-10x+24=0
The zeros of 5x^2-10x+24=0 are x=1+isqrt(19/5),x=1-isqrt(19/5)