What are the solutions to the equation 18x^2+25x-3=0 ?

The solutions to the equation 18x^2+25x-3=0 are x= 1/9 ,x=-3/2

Find the zeros of 18x^2+25x-3=0

The zeros of 18x^2+25x-3=0 are x= 1/9 ,x=-3/2

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18 x^{2} + 25 x - 3 = 0

x = \frac{1}{9}, x = - \frac{3}{2}

Decimal Notation

x = 0.11111 \dots, x = - 1.5

Solution steps

18 x^{2} + 25 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 18 ( - 3 )}{2 \cdot 18}

2 5^{2} - 4 \cdot 18 (- 3) = 29

x_{1, 2} = \frac{- 25 \pm 29}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 25 + 29}{2 \cdot 18}, x_{2} = \frac{- 25 - 29}{2 \cdot 18}

x = \frac{- 25 + 29}{2 \cdot 18} : \frac{1}{9}

x = \frac{- 25 - 29}{2 \cdot 18} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{9}, x = - \frac{3}{2}

9^{2} + 2^{2} = x^{2}

(x + 4) (x + 6) = 0

21 = - x^{2} + 10 x

2 x^{2} - 16 x + 24

2 x^{2} - 3 x - 14 = 0

What are the solutions to the equation 18x^2+25x-3=0 ?
The solutions to the equation 18x^2+25x-3=0 are x= 1/9 ,x=-3/2
Find the zeros of 18x^2+25x-3=0
The zeros of 18x^2+25x-3=0 are x= 1/9 ,x=-3/2