What are the solutions to the equation 21=-x^2+10x ?

The solutions to the equation 21=-x^2+10x are x=3,x=7

Find the zeros of 21=-x^2+10x

The zeros of 21=-x^2+10x are x=3,x=7

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21 = - x^{2} + 10 x

x = 3, x = 7

Solution steps

21 = - x^{2} + 10 x

Switch sides

- x^{2} + 10 x = 21

Move

21

to the left side

- x^{2} + 10 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 21 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 21) = 4

x_{1, 2} = \frac{- 10 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 4}{2 ( - 1 )}, x_{2} = \frac{- 10 - 4}{2 ( - 1 )}

x = \frac{- 10 + 4}{2 ( - 1 )} : 3

x = \frac{- 10 - 4}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = 3, x = 7

2 x^{2} - 16 x + 24

2 x^{2} - 3 x - 14 = 0

(x + 3)^{2} + 20 = 0

x^{2} - 12 x + 40 = 13

x, f = 3 x^{2} + 4 y

What are the solutions to the equation 21=-x^2+10x ?
The solutions to the equation 21=-x^2+10x are x=3,x=7
Find the zeros of 21=-x^2+10x
The zeros of 21=-x^2+10x are x=3,x=7