What are the solutions to the equation (x-1)(x-3)=5 ?

The solutions to the equation (x-1)(x-3)=5 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of (x-1)(x-3)=5

The zeros of (x-1)(x-3)=5 are x=2+sqrt(6),x=2-sqrt(6)

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(x - 1) (x - 3) = 5

x = 2 + 6, x = 2 - 6

Decimal Notation

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

(x - 1) (x - 3) = 5

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

x^{2} - 4 x + 3 = 5

Move

5

to the left side

x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

4 n^{2} + 1 = 157

y, 10 x^{2} - 3 y^{2} = 10

119.286 - 20 x + 7.5 x^{2} = 0

5 x^{2} - 25 x + 12

5^{2} = a^{2} + 3^{2}

What are the solutions to the equation (x-1)(x-3)=5 ?
The solutions to the equation (x-1)(x-3)=5 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of (x-1)(x-3)=5
The zeros of (x-1)(x-3)=5 are x=2+sqrt(6),x=2-sqrt(6)