What are the solutions to the equation 4n^2+1=157 ?

The solutions to the equation 4n^2+1=157 are n=sqrt(39),n=-sqrt(39)

Find the zeros of 4n^2+1=157

The zeros of 4n^2+1=157 are n=sqrt(39),n=-sqrt(39)

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4 n^{2} + 1 = 157

n = 39, n = - 39

Decimal Notation

n = 6.24499 \dots, n = - 6.24499 \dots

Solution steps

4 n^{2} + 1 = 157

Move

1

to the right side

4 n^{2} = 156

Divide both sides by

4

n^{2} = 39

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 39, n = - 39

y, 10 x^{2} - 3 y^{2} = 10

119.286 - 20 x + 7.5 x^{2} = 0

5 x^{2} - 25 x + 12

5^{2} = a^{2} + 3^{2}

m^{2} - 9 m + 8 = 0

What are the solutions to the equation 4n^2+1=157 ?
The solutions to the equation 4n^2+1=157 are n=sqrt(39),n=-sqrt(39)
Find the zeros of 4n^2+1=157
The zeros of 4n^2+1=157 are n=sqrt(39),n=-sqrt(39)