What are the solutions to the equation x^2-10x=1 ?

The solutions to the equation x^2-10x=1 are x=5+sqrt(26),x=5-sqrt(26)

Find the zeros of x^2-10x=1

The zeros of x^2-10x=1 are x=5+sqrt(26),x=5-sqrt(26)

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x^{2} - 10 x = 1

x = 5 + 26, x = 5 - 26

Solution steps

x^{2} - 10 x = 1

Move

1

to the left side

x^{2} - 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 1) = 226

x_{1, 2} = \frac{- ( - 10 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 26}{2 \cdot 1} : 5 + 26

x = \frac{- ( - 10 ) - 2 26}{2 \cdot 1} : 5 - 26

The solutions to the quadratic equation are:

x = 5 + 26, x = 5 - 26

2 (\frac{48}{3})^{- \frac{1}{4}}

- 5 p + 15 > 5

(3 x - 1) (10 x + 4) \geq (6 x - 5) (5 x - 7)

- x^{2} - x + 42

7 (5 w - 3) = - 36 (2 - w)

What are the solutions to the equation x^2-10x=1 ?
The solutions to the equation x^2-10x=1 are x=5+sqrt(26),x=5-sqrt(26)
Find the zeros of x^2-10x=1
The zeros of x^2-10x=1 are x=5+sqrt(26),x=5-sqrt(26)