What are the solutions to the equation factor 2x^2-8x=0 ?

The solutions to the equation factor 2x^2-8x=0 are x=0,x=4

Find the zeros of factor 2x^2-8x=0

The zeros of factor 2x^2-8x=0 are x=0,x=4

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2 x^{2} - 8 x = 0

x = 0, x = 4

Solution steps

2 x^{2} - 8 x = 0

Factor

2 x^{2} - 8 x : 2 x (x - 4)

2 x (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 0, x = 4

p, q = 400 - p^{2}

y = - \frac{1}{20} y^{2}

124 = 0.006 a^{2} - 0.02 a + 120

- x^{2} - 2 x + 7 = - 17

\frac{1}{4} x^{2} - x - 1 = \frac{1}{16} x^{2} - \frac{1}{4} x + \frac{5}{4}

What are the solutions to the equation factor 2x^2-8x=0 ?
The solutions to the equation factor 2x^2-8x=0 are x=0,x=4
Find the zeros of factor 2x^2-8x=0
The zeros of factor 2x^2-8x=0 are x=0,x=4