What are the solutions to the equation x^2-10x-4=10 ?

The solutions to the equation x^2-10x-4=10 are x=5+sqrt(39),x=5-sqrt(39)

Find the zeros of x^2-10x-4=10

The zeros of x^2-10x-4=10 are x=5+sqrt(39),x=5-sqrt(39)

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x^{2} - 10 x - 4 = 10

x = 5 + 39, x = 5 - 39

Decimal Notation

x = 11.24499 \dots, x = - 1.24499 \dots

Solution steps

x^{2} - 10 x - 4 = 10

Move

10

to the left side

x^{2} - 10 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 14) = 239

x_{1, 2} = \frac{- ( - 10 ) \pm 2 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 39}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 39}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 39}{2 \cdot 1} : 5 + 39

x = \frac{- ( - 10 ) - 2 39}{2 \cdot 1} : 5 - 39

The solutions to the quadratic equation are:

x = 5 + 39, x = 5 - 39

x, z = x^{2} + y^{2} + 2 y + 1

4 x^{2} - 9 = 0

x, x^{2} + y^{2} + 2 x - 18 + 78 = 0

3 x^{2} = 4 x + 6

x, x^{2} + 3 = 0

What are the solutions to the equation x^2-10x-4=10 ?
The solutions to the equation x^2-10x-4=10 are x=5+sqrt(39),x=5-sqrt(39)
Find the zeros of x^2-10x-4=10
The zeros of x^2-10x-4=10 are x=5+sqrt(39),x=5-sqrt(39)