What are the solutions to the equation x^2-5x+n+2=0 ?

The solutions to the equation x^2-5x+n+2=0 are x=(5+sqrt(-4n+17))/2 ,x=(5-sqrt(-4n+17))/2

Find the zeros of x^2-5x+n+2=0

The zeros of x^2-5x+n+2=0 are x=(5+sqrt(-4n+17))/2 ,x=(5-sqrt(-4n+17))/2

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x^{2} - 5 x + n + 2 = 0

x = \frac{5 + - 4 n + 17}{2}, x = \frac{5 - - 4 n + 17}{2}

Solution steps

x^{2} - 5 x + n + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( n + 2 )}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot (n + 2) : - 4 n + 17

x_{1, 2} = \frac{- ( - 5 ) \pm - 4 n + 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + - 4 n + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - - 4 n + 17}{2 \cdot 1}

x = \frac{- ( - 5 ) + - 4 n + 17}{2 \cdot 1} : \frac{5 + - 4 n + 17}{2}

x = \frac{- ( - 5 ) - - 4 n + 17}{2 \cdot 1} : \frac{5 - - 4 n + 17}{2}

The solutions to the quadratic equation are:

x = \frac{5 + - 4 n + 17}{2}, x = \frac{5 - - 4 n + 17}{2}

- (x - 2)^{2} + 16 = 0

6 - x^{2} + 8 x = 5 + 4 x

0 = 2.4 + 8.6 x - 4.9 \cdot x^{2}

(x + 49)^{2} = 24

0 = - 10 + n^{2}

What are the solutions to the equation x^2-5x+n+2=0 ?
The solutions to the equation x^2-5x+n+2=0 are x=(5+sqrt(-4n+17))/2 ,x=(5-sqrt(-4n+17))/2
Find the zeros of x^2-5x+n+2=0
The zeros of x^2-5x+n+2=0 are x=(5+sqrt(-4n+17))/2 ,x=(5-sqrt(-4n+17))/2