What are the solutions to the equation 4x^2-11x+1=0 ?

The solutions to the equation 4x^2-11x+1=0 are x=(11+sqrt(105))/8 ,x=(11-sqrt(105))/8

Find the zeros of 4x^2-11x+1=0

The zeros of 4x^2-11x+1=0 are x=(11+sqrt(105))/8 ,x=(11-sqrt(105))/8

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4 x^{2} - 11 x + 1 = 0

x = \frac{11 + 105}{8}, x = \frac{11 - 105}{8}

Decimal Notation

x = 2.65586 \dots, x = 0.09413 \dots

Solution steps

4 x^{2} - 11 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 \cdot 1 = 105

x_{1, 2} = \frac{- ( - 11 ) \pm 105}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 105}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 105}{2 \cdot 4}

x = \frac{- ( - 11 ) + 105}{2 \cdot 4} : \frac{11 + 105}{8}

x = \frac{- ( - 11 ) - 105}{2 \cdot 4} : \frac{11 - 105}{8}

The solutions to the quadratic equation are:

x = \frac{11 + 105}{8}, x = \frac{11 - 105}{8}

a x^{2} + 8 x + c = 0

x^{2} - 12 x + 56 = 0

x^{2} - 10 x - 3 = 5

x, x^{2} - 2 = 0

x^{2} + 2 x - 48 = 0

What are the solutions to the equation 4x^2-11x+1=0 ?
The solutions to the equation 4x^2-11x+1=0 are x=(11+sqrt(105))/8 ,x=(11-sqrt(105))/8
Find the zeros of 4x^2-11x+1=0
The zeros of 4x^2-11x+1=0 are x=(11+sqrt(105))/8 ,x=(11-sqrt(105))/8