What are the solutions to the equation 4x^2-56x+192=0 ?

The solutions to the equation 4x^2-56x+192=0 are x=8,x=6

Find the zeros of 4x^2-56x+192=0

The zeros of 4x^2-56x+192=0 are x=8,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 56 x + 192 = 0

x = 8, x = 6

Solution steps

4 x^{2} - 56 x + 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 4 \cdot 192}{2 \cdot 4}

(- 56)^{2} - 4 \cdot 4 \cdot 192 = 8

x_{1, 2} = \frac{- ( - 56 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 56 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 56 ) - 8}{2 \cdot 4}

x = \frac{- ( - 56 ) + 8}{2 \cdot 4} : 8

x = \frac{- ( - 56 ) - 8}{2 \cdot 4} : 6

The solutions to the quadratic equation are:

x = 8, x = 6

(4 x - 1) (x - 3) = 15

a^{2} + 1 0^{2} = 2 6^{2}

0 = 3 x^{2} - 14 x

10 = 500 - 3 p - p^{2}

- 4 x^{2} - x + 5 = 0

What are the solutions to the equation 4x^2-56x+192=0 ?
The solutions to the equation 4x^2-56x+192=0 are x=8,x=6
Find the zeros of 4x^2-56x+192=0
The zeros of 4x^2-56x+192=0 are x=8,x=6