What are the solutions to the equation a^2+10^2=26^2 ?

The solutions to the equation a^2+10^2=26^2 are a=24,a=-24

Find the zeros of a^2+10^2=26^2

The zeros of a^2+10^2=26^2 are a=24,a=-24

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a^{2} + 1 0^{2} = 2 6^{2}

a = 24, a = - 24

Solution steps

a^{2} + 1 0^{2} = 2 6^{2}

Move

1 0^{2}

to the right side

a^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 576, a = - 576

576 = 24

- 576 = - 24

a = 24, a = - 24

0 = 3 x^{2} - 14 x

10 = 500 - 3 p - p^{2}

- 4 x^{2} - x + 5 = 0

\frac{1}{2} x^{2} - x - 3 = 0

12 x^{2} - x - 6 = 0

What are the solutions to the equation a^2+10^2=26^2 ?
The solutions to the equation a^2+10^2=26^2 are a=24,a=-24
Find the zeros of a^2+10^2=26^2
The zeros of a^2+10^2=26^2 are a=24,a=-24