What are the solutions to the equation (5x-3)(2x+1)=0 ?

The solutions to the equation (5x-3)(2x+1)=0 are x= 3/5 ,x=-1/2

Find the zeros of (5x-3)(2x+1)=0

The zeros of (5x-3)(2x+1)=0 are x= 3/5 ,x=-1/2

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(5 x - 3) (2 x + 1) = 0

x = \frac{3}{5}, x = - \frac{1}{2}

Decimal Notation

x = 0.6, x = - 0.5

Solution steps

(5 x - 3) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 3 = 0 or 2 x + 1 = 0

Solve

5 x - 3 = 0 : x = \frac{3}{5}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{1}{2}

1 - 16 x^{2} = 0

z^{2} + 6 z + 1 = 0

5^{2} + b^{2} = 1 4^{2}

y, y^{2} = (x - y) (x^{2} + y)

60 x^{2} = 0

What are the solutions to the equation (5x-3)(2x+1)=0 ?
The solutions to the equation (5x-3)(2x+1)=0 are x= 3/5 ,x=-1/2
Find the zeros of (5x-3)(2x+1)=0
The zeros of (5x-3)(2x+1)=0 are x= 3/5 ,x=-1/2