What are the solutions to the equation 5^2+b^2=14^2 ?

The solutions to the equation 5^2+b^2=14^2 are b=3sqrt(19),b=-3sqrt(19)

Find the zeros of 5^2+b^2=14^2

The zeros of 5^2+b^2=14^2 are b=3sqrt(19),b=-3sqrt(19)

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5^{2} + b^{2} = 1 4^{2}

b = 319, b = - 319

Decimal Notation

b = 13.07669 \dots, b = - 13.07669 \dots

Solution steps

5^{2} + b^{2} = 1 4^{2}

Move

5^{2}

to the right side

b^{2} = 171

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 171, b = - 171

171 = 319

- 171 = - 319

b = 319, b = - 319

y, y^{2} = (x - y) (x^{2} + y)

60 x^{2} = 0

12 - 12 x^{2} = 0

x^{2} + 32 = 25

x^{2} - 34 x + 264 = 0

What are the solutions to the equation 5^2+b^2=14^2 ?
The solutions to the equation 5^2+b^2=14^2 are b=3sqrt(19),b=-3sqrt(19)
Find the zeros of 5^2+b^2=14^2
The zeros of 5^2+b^2=14^2 are b=3sqrt(19),b=-3sqrt(19)