What are the solutions to the equation x^2-34x+264=0 ?

The solutions to the equation x^2-34x+264=0 are x=22,x=12

Find the zeros of x^2-34x+264=0

The zeros of x^2-34x+264=0 are x=22,x=12

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x^{2} - 34 x + 264 = 0

x = 22, x = 12

Solution steps

x^{2} - 34 x + 264 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 34 ) \pm ( - 34 ) ^{2} - 4 \cdot 1 \cdot 264}{2 \cdot 1}

(- 34)^{2} - 4 \cdot 1 \cdot 264 = 10

x_{1, 2} = \frac{- ( - 34 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 34 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 34 ) - 10}{2 \cdot 1}

x = \frac{- ( - 34 ) + 10}{2 \cdot 1} : 22

x = \frac{- ( - 34 ) - 10}{2 \cdot 1} : 12

The solutions to the quadratic equation are:

x = 22, x = 12

- (x - 1)^{2} = 0

140 - 96 x + 12 x^{2} = 0

7 + 6 x - x^{2}

3 2^{2} + x^{2} = 6 8^{2}

8 x^{2} + 12 x = 0

What are the solutions to the equation x^2-34x+264=0 ?
The solutions to the equation x^2-34x+264=0 are x=22,x=12
Find the zeros of x^2-34x+264=0
The zeros of x^2-34x+264=0 are x=22,x=12