What are the solutions to the equation 140-96x+12x^2=0 ?

The solutions to the equation 140-96x+12x^2=0 are x=(12+sqrt(39))/3 ,x=(12-sqrt(39))/3

Find the zeros of 140-96x+12x^2=0

The zeros of 140-96x+12x^2=0 are x=(12+sqrt(39))/3 ,x=(12-sqrt(39))/3

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140 - 96 x + 12 x^{2} = 0

x = \frac{12 + 39}{3}, x = \frac{12 - 39}{3}

Decimal Notation

x = 6.08166 \dots, x = 1.91833 \dots

Solution steps

140 - 96 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 96 x + 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 12 \cdot 140}{2 \cdot 12}

(- 96)^{2} - 4 \cdot 12 \cdot 140 = 839

x_{1, 2} = \frac{- ( - 96 ) \pm 8 39}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 8 39}{2 \cdot 12}, x_{2} = \frac{- ( - 96 ) - 8 39}{2 \cdot 12}

x = \frac{- ( - 96 ) + 8 39}{2 \cdot 12} : \frac{12 + 39}{3}

x = \frac{- ( - 96 ) - 8 39}{2 \cdot 12} : \frac{12 - 39}{3}

The solutions to the quadratic equation are:

x = \frac{12 + 39}{3}, x = \frac{12 - 39}{3}

7 + 6 x - x^{2}

3 2^{2} + x^{2} = 6 8^{2}

8 x^{2} + 12 x = 0

3 x (5 x - 5) - 5 = 0

6 x^{2} - 200 = 2 (x^{2} + 28)

What are the solutions to the equation 140-96x+12x^2=0 ?
The solutions to the equation 140-96x+12x^2=0 are x=(12+sqrt(39))/3 ,x=(12-sqrt(39))/3
Find the zeros of 140-96x+12x^2=0
The zeros of 140-96x+12x^2=0 are x=(12+sqrt(39))/3 ,x=(12-sqrt(39))/3