What are the solutions to the equation 6x^2-200=2(x^2+28) ?

The solutions to the equation 6x^2-200=2(x^2+28) are x=8,x=-8

Find the zeros of 6x^2-200=2(x^2+28)

The zeros of 6x^2-200=2(x^2+28) are x=8,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 200 = 2 (x^{2} + 28)

x = 8, x = - 8

Solution steps

6 x^{2} - 200 = 2 (x^{2} + 28)

Expand

2 (x^{2} + 28) : 2 x^{2} + 56

6 x^{2} - 200 = 2 x^{2} + 56

Move

200

to the right side

6 x^{2} = 2 x^{2} + 256

Move

2 x^{2}

to the left side

4 x^{2} = 256

Divide both sides by

4

x^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 64, x = - 64

64 = 8

- 64 = - 8

x = 8, x = - 8

x^{2} + 11 x + 20 = 2

(- 2 t - 5) (8 t - 5) = 0

x (x - 10) = 21

x^{2} + 2 = 11

2 x^{2} + 65 x - 200 = 0

What are the solutions to the equation 6x^2-200=2(x^2+28) ?
The solutions to the equation 6x^2-200=2(x^2+28) are x=8,x=-8
Find the zeros of 6x^2-200=2(x^2+28)
The zeros of 6x^2-200=2(x^2+28) are x=8,x=-8