What are the solutions to the equation quadraticformula x^2+6x-8=0 ?

The solutions to the equation quadraticformula x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)

Find the zeros of quadraticformula x^2+6x-8=0

The zeros of quadraticformula x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 6 x - 8 = 0

x = - 3 + 17, x = - 3 - 17

Decimal Notation

x = 1.12310 \dots, x = - 7.12310 \dots

Solution steps

x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 8) = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 17}{2 \cdot 1}

x = \frac{- 6 + 2 17}{2 \cdot 1} : - 3 + 17

x = \frac{- 6 - 2 17}{2 \cdot 1} : - 3 - 17

The solutions to the quadratic equation are:

x = - 3 + 17, x = - 3 - 17

48 = x^{2}

x^{2} + 0 = 0

7 y^{2} - 9 y^{2} = 63

x^{2} + 1 = 4

- (- 5) y + (- 5) = - 5 y^{2} - 5

What are the solutions to the equation quadraticformula x^2+6x-8=0 ?
The solutions to the equation quadraticformula x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)
Find the zeros of quadraticformula x^2+6x-8=0
The zeros of quadraticformula x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)