What are the solutions to the equation x^2+1=4 ?

The solutions to the equation x^2+1=4 are x=sqrt(3),x=-sqrt(3)

Find the zeros of x^2+1=4

The zeros of x^2+1=4 are x=sqrt(3),x=-sqrt(3)

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x^{2} + 1 = 4

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

x^{2} + 1 = 4

Move

1

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

- (- 5) y + (- 5) = - 5 y^{2} - 5

3 (3 x - 2)^{2} = 2 (3 x + 2)

2 k^{2} + 7 k + 6 = 0

x^{2} + 16 x + 46 = 0

2 x^{2} - 7 x - 4 = 0

What are the solutions to the equation x^2+1=4 ?
The solutions to the equation x^2+1=4 are x=sqrt(3),x=-sqrt(3)
Find the zeros of x^2+1=4
The zeros of x^2+1=4 are x=sqrt(3),x=-sqrt(3)