What are the solutions to the equation x^2+16x+46=0 ?

The solutions to the equation x^2+16x+46=0 are x=-8+3sqrt(2),x=-8-3sqrt(2)

Find the zeros of x^2+16x+46=0

The zeros of x^2+16x+46=0 are x=-8+3sqrt(2),x=-8-3sqrt(2)

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x^{2} + 16 x + 46 = 0

x = - 8 + 32, x = - 8 - 32

Decimal Notation

x = - 3.75735 \dots, x = - 12.24264 \dots

Solution steps

x^{2} + 16 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 46 = 62

x_{1, 2} = \frac{- 16 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 16 - 6 2}{2 \cdot 1}

x = \frac{- 16 + 6 2}{2 \cdot 1} : - 8 + 32

x = \frac{- 16 - 6 2}{2 \cdot 1} : - 8 - 32

The solutions to the quadratic equation are:

x = - 8 + 32, x = - 8 - 32

2 x^{2} - 7 x - 4 = 0

2 x^{2} + x - 1 = 0

- x^{2} + x + 56 = 0

6 x^{2} + 5 x - 3 = 0

x, y = a (x - h)^{2} + k

What are the solutions to the equation x^2+16x+46=0 ?
The solutions to the equation x^2+16x+46=0 are x=-8+3sqrt(2),x=-8-3sqrt(2)
Find the zeros of x^2+16x+46=0
The zeros of x^2+16x+46=0 are x=-8+3sqrt(2),x=-8-3sqrt(2)