What are the solutions to the equation factor 2x^2+x-1=0 ?

The solutions to the equation factor 2x^2+x-1=0 are x= 1/2 ,x=-1

Find the zeros of factor 2x^2+x-1=0

The zeros of factor 2x^2+x-1=0 are x= 1/2 ,x=-1

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2 x^{2} + x - 1 = 0

x = \frac{1}{2}, x = - 1

Decimal Notation

x = 0.5, x = - 1

Solution steps

2 x^{2} + x - 1 = 0

Factor

2 x^{2} + x - 1 : (2 x - 1) (x + 1)

(2 x - 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 1

- x^{2} + x + 56 = 0

6 x^{2} + 5 x - 3 = 0

x, y = a (x - h)^{2} + k

- 30 y - 25 = 9 y^{2}

2 x = x^{2} - 8 x + 16

What are the solutions to the equation factor 2x^2+x-1=0 ?
The solutions to the equation factor 2x^2+x-1=0 are x= 1/2 ,x=-1
Find the zeros of factor 2x^2+x-1=0
The zeros of factor 2x^2+x-1=0 are x= 1/2 ,x=-1