What are the solutions to the equation 1/5 m^2+2/5 m+2=0 ?

The solutions to the equation 1/5 m^2+2/5 m+2=0 are m=-1+3i,m=-1-3i

Find the zeros of 1/5 m^2+2/5 m+2=0

The zeros of 1/5 m^2+2/5 m+2=0 are m=-1+3i,m=-1-3i

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\frac{1}{5} m^{2} + \frac{2}{5} m + 2 = 0

m = - 1 + 3 i, m = - 1 - 3 i

Solution steps

\frac{1}{5} m^{2} + \frac{2}{5} m + 2 = 0

Multiply both sides by

5

m^{2} + 2 m + 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 10 : 6 i

m_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 6 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 6 i}{2 \cdot 1}

m = \frac{- 2 + 6 i}{2 \cdot 1} : - 1 + 3 i

m = \frac{- 2 - 6 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

m = - 1 + 3 i, m = - 1 - 3 i

3 x^{2} - 2 x - 20 = 13 x - 2

4 y^{2} - 13 = y^{2} + 14

s^{2} + 9 s + 7 = 0

x^{2} = - 9 x + 15

(a x + 5)^{2} = 16 x^{2} + b x + 25

What are the solutions to the equation 1/5 m^2+2/5 m+2=0 ?
The solutions to the equation 1/5 m^2+2/5 m+2=0 are m=-1+3i,m=-1-3i
Find the zeros of 1/5 m^2+2/5 m+2=0
The zeros of 1/5 m^2+2/5 m+2=0 are m=-1+3i,m=-1-3i