What are the solutions to the equation x^2-20x-25=0 ?

The solutions to the equation x^2-20x-25=0 are x=5(2+sqrt(5)),x=5(2-sqrt(5))

Find the zeros of x^2-20x-25=0

The zeros of x^2-20x-25=0 are x=5(2+sqrt(5)),x=5(2-sqrt(5))

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x^{2} - 20 x - 25 = 0

x = 5 (2 + 5), x = 5 (2 - 5)

Decimal Notation

x = 21.18033 \dots, x = - 1.18033 \dots

Solution steps

x^{2} - 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 25) = 105

x_{1, 2} = \frac{- ( - 20 ) \pm 10 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10 5}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 10 5}{2 \cdot 1}

x = \frac{- ( - 20 ) + 10 5}{2 \cdot 1} : 5 (2 + 5)

x = \frac{- ( - 20 ) - 10 5}{2 \cdot 1} : 5 (2 - 5)

The solutions to the quadratic equation are:

x = 5 (2 + 5), x = 5 (2 - 5)

2 x^{2} - 10 x + 6 = 0

- 3 x^{2} - 60 x - 230.5 = 0

\frac{1}{3} x^{2} = - 15

x^{2} - 3 x + 20 = 0

4 - 3 x - x^{2} = (3 x - 2)^{2} - 1

What are the solutions to the equation x^2-20x-25=0 ?
The solutions to the equation x^2-20x-25=0 are x=5(2+sqrt(5)),x=5(2-sqrt(5))
Find the zeros of x^2-20x-25=0
The zeros of x^2-20x-25=0 are x=5(2+sqrt(5)),x=5(2-sqrt(5))