What are the solutions to the equation 12x^2+x-1=0 ?

The solutions to the equation 12x^2+x-1=0 are x= 1/4 ,x=-1/3

Find the zeros of 12x^2+x-1=0

The zeros of 12x^2+x-1=0 are x= 1/4 ,x=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} + x - 1 = 0

x = \frac{1}{4}, x = - \frac{1}{3}

Decimal Notation

x = 0.25, x = - 0.33333 \dots

Solution steps

12 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 12 ( - 1 )}{2 \cdot 12}

1^{2} - 4 \cdot 12 (- 1) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 12}, x_{2} = \frac{- 1 - 7}{2 \cdot 12}

x = \frac{- 1 + 7}{2 \cdot 12} : \frac{1}{4}

x = \frac{- 1 - 7}{2 \cdot 12} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{1}{3}

z, x^{2} + y^{2} + z^{2} = 4

2 x^{2} + x - 10 = 0

- 3 x^{2} - 2 x + 2 = 0

0 = - (\frac{8}{3}) x^{2} + 48 x - 192

0 = 2 x^{2} - 14 x + 9

What are the solutions to the equation 12x^2+x-1=0 ?
The solutions to the equation 12x^2+x-1=0 are x= 1/4 ,x=-1/3
Find the zeros of 12x^2+x-1=0
The zeros of 12x^2+x-1=0 are x= 1/4 ,x=-1/3