What are the solutions to the equation 0=2x^2-14x+9 ?

The solutions to the equation 0=2x^2-14x+9 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2

Find the zeros of 0=2x^2-14x+9

The zeros of 0=2x^2-14x+9 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2

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0 = 2 x^{2} - 14 x + 9

x = \frac{7 + 31}{2}, x = \frac{7 - 31}{2}

Decimal Notation

x = 6.28388 \dots, x = 0.71611 \dots

Solution steps

0 = 2 x^{2} - 14 x + 9

Switch sides

2 x^{2} - 14 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 9 = 231

x_{1, 2} = \frac{- ( - 14 ) \pm 2 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 31}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 31}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 31}{2 \cdot 2} : \frac{7 + 31}{2}

x = \frac{- ( - 14 ) - 2 31}{2 \cdot 2} : \frac{7 - 31}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 31}{2}, x = \frac{7 - 31}{2}

15 x^{2} - 8 = 14 x

u^{2} - 12 u

4 x^{2} - 5 = 11 x

x^{2} - 19 = 30

5 (x - 3)^{2} = 45

What are the solutions to the equation 0=2x^2-14x+9 ?
The solutions to the equation 0=2x^2-14x+9 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2
Find the zeros of 0=2x^2-14x+9
The zeros of 0=2x^2-14x+9 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2