What are the solutions to the equation 18(-x^2+1)=0 ?

The solutions to the equation 18(-x^2+1)=0 are x=1,x=-1

Find the zeros of 18(-x^2+1)=0

The zeros of 18(-x^2+1)=0 are x=1,x=-1

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18 (- x^{2} + 1) = 0

x = 1, x = - 1

Solution steps

18 (- x^{2} + 1) = 0

Divide both sides by

18

- x^{2} + 1 = 0

Move

1

to the right side

- x^{2} = - 1

Divide both sides by

- 1

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

1 = 3 x^{2} - 3

(3 x + 2) (4 x - 5) = 0

3 (x - 1) (x + 2) = 3 x - 6

x^{2} - 0.5625 x^{2} + 2 x^{2} - 2 x - 3 + 5 (2 x) = 0

\frac{x ^{2}}{12} - \frac{x}{6} = 1

What are the solutions to the equation 18(-x^2+1)=0 ?
The solutions to the equation 18(-x^2+1)=0 are x=1,x=-1
Find the zeros of 18(-x^2+1)=0
The zeros of 18(-x^2+1)=0 are x=1,x=-1