What are the solutions to the equation (x^2)/(12)-x/6 =1 ?

The solutions to the equation (x^2)/(12)-x/6 =1 are x=1+sqrt(13),x=1-sqrt(13)

Find the zeros of (x^2)/(12)-x/6 =1

The zeros of (x^2)/(12)-x/6 =1 are x=1+sqrt(13),x=1-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{2}}{12} - \frac{x}{6} = 1

x = 1 + 13, x = 1 - 13

Decimal Notation

x = 4.60555 \dots, x = - 2.60555 \dots

Solution steps

\frac{x ^{2}}{12} - \frac{x}{6} = 1

Find Least Common Multiplier of

12, 6 : 12

Multiply by LCM=

12

\frac{x ^{2}}{12} \cdot 12 - \frac{x}{6} \cdot 12 = 1 \cdot 12

Simplify

x^{2} - 2 x = 12

Move

12

to the left side

x^{2} - 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 12) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 1} : 1 + 13

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 1} : 1 - 13

The solutions to the quadratic equation are:

x = 1 + 13, x = 1 - 13

9 k^{2} + 18 k - 40 = 0

- 4 = - 7 k^{2}

(x + 1) (x + 4) = 0

0 = x^{2} + 11 x

72 x - 12 x^{2} = 0

What are the solutions to the equation (x^2)/(12)-x/6 =1 ?
The solutions to the equation (x^2)/(12)-x/6 =1 are x=1+sqrt(13),x=1-sqrt(13)
Find the zeros of (x^2)/(12)-x/6 =1
The zeros of (x^2)/(12)-x/6 =1 are x=1+sqrt(13),x=1-sqrt(13)