What are the solutions to the equation -4=-7k^2 ?

The solutions to the equation -4=-7k^2 are k= 2/(sqrt(7)),k=-2/(sqrt(7))

Find the zeros of -4=-7k^2

The zeros of -4=-7k^2 are k= 2/(sqrt(7)),k=-2/(sqrt(7))

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- 4 = - 7 k^{2}

k = \frac{2}{7}, k = - \frac{2}{7}

Decimal Notation

k = 0.75592 \dots, k = - 0.75592 \dots

Solution steps

- 4 = - 7 k^{2}

Switch sides

- 7 k^{2} = - 4

Divide both sides by

- 7

k^{2} = \frac{4}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = \frac{4}{7}, k = - \frac{4}{7}

\frac{4}{7} = \frac{2}{7}

- \frac{4}{7} = - \frac{2}{7}

k = \frac{2}{7}, k = - \frac{2}{7}

(x + 1) (x + 4) = 0

0 = x^{2} + 11 x

72 x - 12 x^{2} = 0

x^{2} + 3 x + 1 = 153

x^{2} + x = 110

What are the solutions to the equation -4=-7k^2 ?
The solutions to the equation -4=-7k^2 are k= 2/(sqrt(7)),k=-2/(sqrt(7))
Find the zeros of -4=-7k^2
The zeros of -4=-7k^2 are k= 2/(sqrt(7)),k=-2/(sqrt(7))